x-intercept of a line (video) | Khan Academy (2024)

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  • retrest

    6 years agoPosted 6 years ago. Direct link to retrest's post “How do you find the y int...”

    How do you find the y intercept?

    (19 votes)

    • michael Li

      6 years agoPosted 6 years ago. Direct link to michael Li's post “You can take the function...”

      x-intercept of a line (video) | Khan Academy (4)

      You can take the function f(x) = something (your funtion) so like f(x)=2x. you can input x=0 and find the output which would be the y intercept. So, lets actually have f(x) = 5x + 2. You input 0 for x and you get f(x) = 2. That is your y intercept

      (24 votes)

  • Ani-Jay

    7 years agoPosted 7 years ago. Direct link to Ani-Jay's post “How do you know where to ...”

    How do you know where to put your intercepts when answering the problems.? I haven't been able to get 100% on the practice problems, because my answers need to be reversed, but I can't figure out where to place them.

    (11 votes)

    • bgale28

      7 months agoPosted 7 months ago. Direct link to bgale28's post “in slope-intercept form, ...”

      in slope-intercept form, ( y=mx+b ) b represents your y-intercept.

      (5 votes)

  • for example how would you find the x intercept for a problem like this ?Y = x2 + 5x + 4
    y = x squared plus five x plus four

    (5 votes)

    • Rachel

      10 years agoPosted 10 years ago. Direct link to Rachel's post “It's a quadratic equation...”

      x-intercept of a line (video) | Khan Academy (11)

      It's a quadratic equation, which means it's a non-linear (is parabolic in shape). You can find the x-intercepts (usually there are 2, but there can be 1 or none) by completing the square, factoring or by using the quadratic formula. Which method I use depends on which one I think will make solving the problem easier. The easiest way to solve is to factor the quadratic equation.
      x^2+5x+4=0

      We set it equal to zero because we are looking for the x intercepts.
      When y is 0 where will the parabola cross the x-axis

      To solve by factoring we ask ourselves: What two numbers add up to the middle term and are the product of the last term?
      4*1=4 (last term)
      4+1=5 (middle term)
      (x+4) (x+1)
      set them both equal to zero to find the x intercept
      x+4=0
      subtract 4 from both sides
      x=-4
      x+1=0
      subtract 1 from both sides
      x=-1
      x intercepts are -4 and -1. Or the points where the parabola crosses the x-axis are (-4,0) and (-1,0).

      (11 votes)

  • Sara Beth

    8 years agoPosted 8 years ago. Direct link to Sara Beth's post “Can't you find the interc...”

    Can't you find the intercept by doing -b/2a, or is that finding the vertex?

    (5 votes)

    • KathyC

      8 years agoPosted 8 years ago. Direct link to KathyC's post “A vertex is a corner, whe...”

      A vertex is a corner, where two lines meet. A straight line by itself doesn't have a vertex.

      The easiest way to find the x intercept is to figure out what value x will have when y = 0.
      So if you have an equation of a line: 2y + 4x = 28
      you substitue "0" in for your y and solve:
      2 (0) + 4x = 28
      4x = 28
      x = 7
      The x intercept is (7,0)

      (8 votes)

  • poodoo

    a year agoPosted a year ago. Direct link to poodoo's post “at 0:48 where did 0 come ...”

    at

    x-intercept of a line (video) | Khan Academy (16) 0:48

    where did 0 come from?

    (6 votes)

    • Venkata

      a year agoPosted a year ago. Direct link to Venkata's post “We need to find the x int...”

      We need to find the x intercept. So, as it is a point on the x axis, the y coordinate has to be 0. So, we substitute y = 0 into the equation.

      (4 votes)

  • daP0l15hc0unt

    6 years agoPosted 6 years ago. Direct link to daP0l15hc0unt's post “Slope intercept form is y...”

    Slope intercept form is y=mx+b.
    Is there a way to use the x-intercept instead of the y-intercept. Use p for the y-intercept in your equation.

    My attempt:
    y = mx + b
    0 = mx + b
    0 = x + b/m
    x = -b/m
    let p be the x-intercept
    therefore: p = -b/m
    Therefore:y = mx - mp
    Am I right?

    (5 votes)

    • KoJesko

      6 years agoPosted 6 years ago. Direct link to KoJesko's post “If m = 3 and b = 2 (Subst...”

      If m = 3 and b = 2 (Substitute) 0 = 3x + 2 (0 = mx + b) (Subtract b from both sides)
      0-2 = 3x (y-b = mx) -2 = 3x (y-b = mx) (divide both sides by the amount x is multiplied by) -2/3 = x

      (5 votes)

  • Ammon Trump

    6 years agoPosted 6 years ago. Direct link to Ammon Trump's post “How would I find the x an...”

    How would I find the x and y intercepts and graph them if I have a function 3x - 5y=15

    (6 votes)

    • bgale28

      7 months agoPosted 7 months ago. Direct link to bgale28's post “You can substitute the x ...”

      You can substitute the x or y to find the other intercept or vice versa. For example, if x was zero in 3x - 5y = 15 then your y-intercept is -3. Or for example, if y was zero in 3x - 5y = 15 then your y-intercept is 5.

      (1 vote)

  • rreid

    5 months agoPosted 5 months ago. Direct link to rreid's post “i understood nothing in t...”

    i understood nothing in the video

    (5 votes)

    • Angelina

      11 days agoPosted 11 days ago. Direct link to Angelina's post “I can explain!The x-int...”

      I can explain!

      The x-intercept of a line is the point at which the line crosses the x-axis.

      In other words, it’s the value of x when y equals zero in the equation of the line.

      For a line represented by the equation y=mx+b,
      where m is the slope and b is the y-intercept, the x-intercept can be found by setting y to zero and solving for x.

      So, if we set y to zero, we get:

      0=mx+b

      Solving for x gives us:

      x=−b/m

      This value of x is the x-intercept of the line. It represents the point on the x-axis where the line intersects. If the line never crosses the x-axis, then it has no x-intercept.

      For example, the line

      y=2x+3

      has an x-intercept at x=−3/2
      or x=−1.5.

      This means the line crosses the x-axis at the point (-1.5, 0).

      I hope this explanation helps! Let me know if you have any other questions.

      (1 vote)

  • Dooder

    9 months agoPosted 9 months ago. Direct link to Dooder's post “Theoretically could there...”

    Theoretically could there be a "z" axis?
    Like on a 3 dimensional graph?
    Do those exist?

    (3 votes)

    • cameronsmith

      8 months agoPosted 8 months ago. Direct link to cameronsmith's post “Yes, we could have a z-ax...”

      Yes, we could have a z-axis. You could graph planes, spheres, and all sorts of other figures. You probably won’t run into 3D graphs unless you do higher-level math. Here is an article on 3D space from the multivariable calculus course: https://www.khanacademy.org/math/multivariable-calculus/thinking-about-multivariable-function/ways-to-represent-multivariable-functions/a/multidimensional-graphs

      You probably won’t understand all of it yet, but you might find it interesting!

      (3 votes)

  • Nakulisthebest

    2 years agoPosted 2 years ago. Direct link to Nakulisthebest's post “I have a question what is...”

    I have a question what is the equation of x intercept?

    (3 votes)

    • Kim Seidel

      2 years agoPosted 2 years ago. Direct link to Kim Seidel's post “There is no equation. Yo...”

      There is no equation. You take the linear equation that you have and you replace Y with 0. Then, solve for X. You will have a point on the line at (x-value, 0) where the x-value is the value you found. This point is where the line cross the x-axis (so, it is the x-intercept).

      (2 votes)

x-intercept of a line (video) | Khan Academy (2024)

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